Four points A(6,3),B(−3,5),C(4,−2) and D(x,2x) are given in such a way that (AreaofABC)(AreaofDBC)=21˙

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Four points {A}{({6},{3})},{B}{(-{3},{5})},{C}{({4},-{2})} and

Question

Four points $A (6, 3), B (- 3, 5), C (4, - 2)$ and $D (x, 2 x)$ are given in such a way that $\frac{( A r e a o f D B C )}{( A r e a o f A B C )} = \frac{1}{2} ˙$

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Theodore Discussed

Four points

A (6, 3), B (- 3, 5), C (4, - 2)

and

D (x, 2 x)

are given in such a way that

\frac{( A r e a o f D B C )}{( A r e a o f A B C )} = \frac{1}{2} ˙

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Question Text

Four points

A (6, 3), B (- 3, 5), C (4, - 2)

and

D (x, 2 x)

are given in such a way that

\frac{( A r e a o f D B C )}{( A r e a o f A B C )} = \frac{1}{2} ˙