Find the area enclosed by the figure described by the equation x4+1=2x2+y2.
Find the area bounded by the curve f(x)=x+sinxand its inverse function between the ordinates x=0 to x=2π.
Consider curves y=x21,y=4(x−1)1. Let α be the value of a(a>2) for which area bounded by curves between x=2andx=a is 1/a is e2+1andβ be the of b∈(1,2), for which the area bounded by curves between x=b and x=2 is 1−b1, then
Let R be the region containing the point (x, y) on the X-Y plane, satisfying 2≤∣x+3y∣+∣x−y∣≤4. Then the area of this region is
The area enclosed by the curve y=4−x2,y≥2sin(22xπ, and the x-axis is divided by the y-axis in the ratio