Find the area bounded by y2≤4x,x2+y2≥2x,andx≤y+2 in the first quadrant.
The area of the region whose boundaries are defined by the curves y=2 cos x, y=3 tan x, and the y-axis is
Which of the following is the possible value/values of c for which the area of the figure bounded by the curves y=sin2x, the straight lines x=π/6,x=c and the abscissa axis is equal to 1/2?
If (a,0), agt 0, is the point where the curve y=sin2x−3sinx cuts the x-axis first, A is the area bounded by this part of the curve, the origin and the positive x-axis. Then
The positive valu of the parameter 'k' for which the area of the figure bounded by the curve y=sin(kx),x=3k2π,x=3k5π and x-axis is less than 2 can be