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Find the A.P whose $$1st$$ term is $$10$$ & common difference is $$5$$. Each term of the AP is divisible by M$$\in N;\ne1$$. Find M
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Given, $$a=10, d=5$$
$$a_1=10$$
$$a_2=a+d=10+5=15$$
$$a_3=a+2d=10+10=20$$
$$a_4=a+3d=10+15=25$$
Hence, AP is $$10,15,20,25.....$$
$$a_1=10$$
$$a_2=a+d=10+5=15$$
$$a_3=a+2d=10+10=20$$
$$a_4=a+3d=10+15=25$$
Hence, AP is $$10,15,20,25.....$$
Every term is divisible by 5
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Divide 20 into four parts which are in A.P. and such that the product of the first and fourth is to the product of the second and third in the ratio 2:3.
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| Question Text | Find the A.P whose $$1st$$ term is $$10$$ & common difference is $$5$$. Each term of the AP is divisible by M$$\in N;\ne1$$. Find M |
| Answer Type | Text solution:1 |
| Upvotes | 150 |
