i24+(i1)26i4=1=1+i21=i2i2+1 =0 (As i2=−1)

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Evaluate: i^{24} + ({1}{i})^{26}

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Evaluate: $i^{24} + (\frac{1}{i})^{26}$

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Text solutionVerified

i^{24} + (\frac{1}{i})^{26}

i^{4} = 1

= 1 + \frac{1}{i ^{2}}

= \frac{i ^{2} + 1}{i ^{2}} = 0

(As

i^{2} = - 1

)

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