Equation of a circle having radius equal to twice the radius of the circle $x^{2} + y^{2} + (2 p + 3) x + (3 - 2 p) y + p - 3 = 0$ and touching it at the origin is

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Equation of a circle having radius equal to twice the radius of the circle

x^{2} + y^{2} + (2 p + 3) x + (3 - 2 p) y + p - 3 = 0

and touching it at the origin is

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Question Text

Equation of a circle having radius equal to twice the radius of the circle

x^{2} + y^{2} + (2 p + 3) x + (3 - 2 p) y + p - 3 = 0

and touching it at the origin is

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