Consider f(x)=tan−1(1−sinx1+sinx),x∈(0,2π)˙A normal to y=f(x)at x=6πalso passes through the point:

Click here to view the solution.

Get 2 FREE Instant-Explanations on Filo with code FILOAPP

Consider {f{{({x})}}}={{}^{{-{1}}}{({{{{{1}+{{{x}}}}}{{{1}-{{{

Question

Consider $f (x) = tan^{- 1} (\frac{1 + sin x}{1 - sin x}), x \in (0, \frac{π}{2}) ˙$ A normal to $y = f (x)$ at $x = \frac{π}{6}$ also passes through the point:

(0, 0)

(0, \frac{2 π}{3})

(\frac{π}{6}, 0)

(\frac{π}{4}, 0)

Views: 853 students

Found 6 tutors discussing this question

Scarlett Discussed

Consider

f (x) = tan^{- 1} (\frac{1 + sin x}{1 - sin x}), x \in (0, \frac{π}{2}) ˙

A normal to

y = f (x)

x = \frac{π}{6}

also passes through the point:

12 mins ago

Discuss this question LIVE

12 mins ago

Question Text

Consider

f (x) = tan^{- 1} (\frac{1 + sin x}{1 - sin x}), x \in (0, \frac{π}{2}) ˙

A normal to

y = f (x)

x = \frac{π}{6}

also passes through the point: