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Complete activity from the following : First term and common

Question

Complete activity from the following :

First term and common difference of an A.P. are $6$ and $3$ respectively . Find $S_{27}$ .
Solution :
First term $= a = 6$ , common difference $= d = 3, S_{27} = ?$
$S_{n} = \frac{n}{2} [□ + (n - 1) d]$ - formula
$S_{27} = \frac{27}{2} [12 + (27 - 1) □]$
$= \frac{27}{2} \times □$
$= 27 \times 45$
$∴ S_{27} = □$

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Complete activity from the following :

First term and common difference of an A.P. are

6

and

3

respectively . Find

S_{27}

.
Solution :
First term

= a = 6

, common difference

= d = 3, S_{27} = ?

S_{n} = \frac{n}{2} [□ + (n - 1) d]

- formula

S_{27} = \frac{27}{2} [12 + (27 - 1) □]

= \frac{27}{2} \times □

= 27 \times 45

∴ S_{27} = □

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Text solutionVerified

Given

a = 6, d = 3

S_{n} = \frac{n}{2} [2 a + (n - 1) d]

S_{27} = \frac{27}{2} [12 + (27 - 1) (3)]

= \frac{27}{2} [12 + 26 \times 3]

= \frac{27}{2} [12 + 78]

= \frac{27}{2} [90]

= 27 \times 45

∴ S_{27} = 1215

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Question Text	Complete activity from the following : First term and common difference of an A.P. are $6$ and $3$ respectively . Find $S_{27}$ . Solution : First term $= a = 6$ , common difference $= d = 3, S_{27} = ?$ $S_{n} = \frac{n}{2} [□ + (n - 1) d]$ - formula $S_{27} = \frac{27}{2} [12 + (27 - 1) □]$ $= \frac{27}{2} \times □$ $= 27 \times 45$ $∴ S_{27} = □$
Answer Type	Text solution:1
Upvotes	150