Change the following from exponential form to logarithmic form.(i) 34=81(ii) 6−4=12961(iii) (811 ) 43 =271(iv) (216) 31 =6(v) (13) −1=131

(i) 34=81⟹log381=4(ii) 6−4=12961⟹log6(12961 ) =−4(iii) (811 ) 43 =271⟹log811 (271 ) =43(iv) (216) 31 =6⟹log2166=31(v) (13) −1=131⟹log13(131 ) =−1

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Change the following from exponential form to logarithmic form

Question

Change the following from exponential form to logarithmic form.
(i) $3^{4} = 81$
(ii) $6^{- 4} = \frac{1}{1296}$
(iii) $(\frac{1}{81})^{\frac{3}{4}} = \frac{1}{27}$
(iv) $(216)^{\frac{1}{3}} = 6$
(v) $(13)^{- 1} = \frac{1}{13}$

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Levi Discussed

Change the following from exponential form to logarithmic form.
(i)

3^{4} = 81

(ii)

6^{- 4} = \frac{1}{1296}

(iii)

(\frac{1}{81})^{\frac{3}{4}} = \frac{1}{27}

(iv)

(216)^{\frac{1}{3}} = 6

(v)

(13)^{- 1} = \frac{1}{13}

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(i)

3^{4} = 81 ⟹ lo g_{3} 81 = 4

(ii)

6^{- 4} = \frac{1}{1296} ⟹ lo g_{6} (\frac{1}{1296}) = - 4

(iii)

(\frac{1}{81})^{\frac{3}{4}} = \frac{1}{27} ⟹ lo g_{\frac{1}{81}} (\frac{1}{27}) = \frac{3}{4}

(iv)

(216)^{\frac{1}{3}} = 6 ⟹ lo g_{216} 6 = \frac{1}{3}

(v)

(13)^{- 1} = \frac{1}{13} ⟹ lo g_{13} (\frac{1}{13}) = - 1

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Question Text	Change the following from exponential form to logarithmic form. (i) $3^{4} = 81$ (ii) $6^{- 4} = \frac{1}{1296}$ (iii) $(\frac{1}{81})^{\frac{3}{4}} = \frac{1}{27}$ (iv) $(216)^{\frac{1}{3}} = 6$ (v) $(13)^{- 1} = \frac{1}{13}$
Answer Type	Text solution:1
Upvotes	150