A square is incribed in a circle $x^{2} + y^{2} - 6 x + 8 y - 103 = 0$ such that its sides are parallel to co-ordinate axis then the distance of the nearest vertex to origin, is equal to (A) $13$ (B) $127$ (C) $41$ (D) $1$

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A square is incribed in a circle

x^{2} + y^{2} - 6 x + 8 y - 103 = 0

such that its sides are parallel to co-ordinate axis then the distance of the nearest vertex to origin, is equal to (A)

13

(B)

127

(C)

41

(D)

1

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Question Text

A square is incribed in a circle

x^{2} + y^{2} - 6 x + 8 y - 103 = 0

such that its sides are parallel to co-ordinate axis then the distance of the nearest vertex to origin, is equal to (A)

13

(B)

127

(C)

41

(D)

1

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