Get 2 FREE Instant-Explanations on Filo with code FILOAPP

A square is incribed in a circle {x}^{{2}}+{y}^{{2}}-{6}{x}+{8

Question

A square is incribed in a circle $x^{2} + y^{2} - 6 x + 8 y - 103 = 0$ such that its sides are parallel to co-ordinate axis then the distance of the nearest vertex to origin, is equal to (A) $13$ (B) $127$ (C) $41$ (D) $1$

Views: 907 students

Found 8 tutors discussing this question

Harper Discussed

A square is incribed in a circle

x^{2} + y^{2} - 6 x + 8 y - 103 = 0

such that its sides are parallel to co-ordinate axis then the distance of the nearest vertex to origin, is equal to (A)

13

(B)

127

(C)

41

(D)

1

13 mins ago

Discuss this question LIVE

13 mins ago

Filo tutor solutions (1)

Learn from their 1-to-1 discussion with Filo tutors.

Ask your question, on a video call with tutor

Connect instantly with this tutor

Connect now

Was this solution helpful?

150

Report

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our maths tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	A square is incribed in a circle $x^{2} + y^{2} - 6 x + 8 y - 103 = 0$ such that its sides are parallel to co-ordinate axis then the distance of the nearest vertex to origin, is equal to (A) $13$ (B) $127$ (C) $41$ (D) $1$
Answer Type	Video solution: 1
Upvotes	150