Without using trigonometric tables, prove that:
$tan^{2} 66^{o} - cot^{2} 24^{o} = 0$

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Without using trigonometric tables, prove that:

tan^{2} 66^{o} - cot^{2} 24^{o} = 0

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Text solutionVerified

L H S = tan^{2} 66^{o} - cot^{2} 24^{o} = tan^{2} 66^{o} - cot^{2} (90 - 66)^{o} = tan^{2} 66^{o} - tan^{2} 66^{o} = 0 = R H S

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Question Text	Without using trigonometric tables, prove that: $tan^{2} 66^{o} - cot^{2} 24^{o} = 0$
Answer Type	Text solution:1
Upvotes	150