Without using trigonometric tables, prove that:
$sin^{o} 48^{o} + sin^{o} 42^{o} = 1$

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Without using trigonometric tables, prove that:

sin^{o} 48^{o} + sin^{o} 42^{o} = 1

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Text solutionVerified

L H S = sin^{2} 48^{o} + sin^{2} 42^{o} = sin^{2} 48^{o} + sin^{2} (90 - 48)^{o} = sin^{2} 48^{o} + cos^{2} 48^{o} = 1 = R H S

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Question Text	Without using trigonometric tables, prove that: $sin^{o} 48^{o} + sin^{o} 42^{o} = 1$
Answer Type	Text solution:1
Upvotes	150