Without using trigonometric tables, prove that:
$co sec^{2} 72^{o} - tan^{2} 18^{o} = 1$

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Without using trigonometric tables, prove that:

co sec^{2} 72^{o} - tan^{2} 18^{o} = 1

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Text solutionVerified

L H S = co sec^{2} 72^{o} - tan^{2} 18^{o} = co sec^{2} 72^{o} - tan^{2} (90 - 72)^{o} = co sec^{2} 72^{o} - cot^{2} 72 = 1 = R H S

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Question Text	Without using trigonometric tables, prove that: $co sec^{2} 72^{o} - tan^{2} 18^{o} = 1$
Answer Type	Text solution:1
Upvotes	150