Without using trigonometric tables, evaluate:sec48o cosec42o

sec48o cosec42o =1/cos48o 1/sin42o =sin(90o−48o) cos48o =cos48o cos48o =1

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Without using trigonometric tables, evaluate: { co { { 42 }^{

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Without using trigonometric tables, evaluate:
$\frac{co sec 42 ^{o}}{sec 48 ^{o}}$

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Emma Discussed

Without using trigonometric tables, evaluate:

\frac{co sec 42 ^{o}}{sec 48 ^{o}}

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\frac{co sec 42 ^{o}}{sec 48 ^{o}} = \frac{1/ sin 42 ^{o}}{1/ cos 48 ^{o}} = \frac{cos 48 ^{o}}{sin ( 90 ^{o} - 48 ^{o} )} = \frac{cos 48 ^{o}}{cos 48 ^{o}} = 1

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Question Text	Without using trigonometric tables, evaluate: $\frac{co sec 42 ^{o}}{sec 48 ^{o}}$
Answer Type	Text solution:1
Upvotes	150