Without using trigonometric tables, evaluate:sin55o cos35o

sin55o cos35o =sin(90o−35o) cos35o =cos35o cos35o =1

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Without using trigonometric tables, evaluate: { { { 35 }^{ o

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Without using trigonometric tables, evaluate:
$\frac{cos 35 ^{o}}{sin 55 ^{o}}$

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Henry Discussed

Without using trigonometric tables, evaluate:

\frac{cos 35 ^{o}}{sin 55 ^{o}}

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\frac{cos 35 ^{o}}{sin 55 ^{o}} = \frac{cos 35 ^{o}}{sin ( 90 ^{o} - 35 ^{o} )} = \frac{cos 35 ^{o}}{cos 35 ^{o}} = 1

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Question Text	Without using trigonometric tables, evaluate: $\frac{cos 35 ^{o}}{sin 55 ^{o}}$
Answer Type	Text solution:1
Upvotes	150