Without trigonometric tables, prove that:
$sin 35^{o} sin 55^{o} - cos 35^{o} cos 55^{o} = 0$

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Without trigonometric tables, prove that:

sin 35^{o} sin 55^{o} - cos 35^{o} cos 55^{o} = 0

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Text solutionVerified

L H S = sin 35^{o} sin 55^{o} - cos 35^{o} cos 55^{o} = sin (90^{o} - 55^{o}) sin (90^{o} - 55^{o}) - cos 35^{o} cos 55^{o}

= cos 55^{o} cos 55^{o} - cos 55^{o} cos 55^{o} = 0 = R H S

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Question Text	Without trigonometric tables, prove that: $sin 35^{o} sin 55^{o} - cos 35^{o} cos 55^{o} = 0$
Answer Type	Text solution:1
Upvotes	150