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Using factor theorem, show that g(x) is a factor of p(x), when

Question

Using factor theorem, show that $g (x)$ is a factor of $p (x)$ , when $p (x) = x^{3} - 8$ , $g (x) = x - 2$ .

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Charlotte Discussed

Using factor theorem, show that

g (x)

is a factor of

p (x)

, when

p (x) = x^{3} - 8

g (x) = x - 2

7 mins ago

Discuss this question LIVE

7 mins ago

Text solutionVerified

use factor theorem,

g (x) = x - 2 = 0

x = 2

p (x) = x^{3} - 8

= (2)^{3} - 8

= 8 - 8 = 0

g (x)

is a factor of

p (x)

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Question Text	Using factor theorem, show that $g (x)$ is a factor of $p (x)$ , when $p (x) = x^{3} - 8$ , $g (x) = x - 2$ .
Answer Type	Text solution:1
Upvotes	150