The value of tanθ⋅tan(90−θ) is equal to

tanθ⋅tan(90−θ) =tanθ×cotθ =1 ∵ tan(90−θ)=cotθ

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The value of {}{(90-)} is equal to

Question

The value of $tan θ \cdot tan (90 - θ)$ is equal to

sin^{2} θ

1

cos^{2} θ

0

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The value of

tan θ \cdot tan (90 - θ)

is equal to

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tan θ \cdot tan (90 - θ) = tan θ \times cot θ = 1

∵ tan (90 - θ) = cot θ

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Question Text	The value of $tan θ \cdot tan (90 - θ)$ is equal to
Answer Type	Text solution:1
Upvotes	150