The value of sin23o 2cos67o −cot50o tan40o −sin90o is :

sin23o 2cos67o +cot50o tan40o −sin90o =cos(90o−23o) 2cos67o −tan(90o−50o) tan40o −sin90o =cos67o 2cos67o −tan40o tan40o −sin90o =2−1−1=0

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The value of { 2 { { 67 }^{ o } } }{ { { 23 }^{ o } } } -

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The value of $\frac{2 cos 67 ^{o}}{sin 23 ^{o}} - \frac{tan 40 ^{o}}{cot 50 ^{o}} - sin 90^{o}$ is :

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The value of

\frac{2 cos 67 ^{o}}{sin 23 ^{o}} - \frac{tan 40 ^{o}}{cot 50 ^{o}} - sin 90^{o}

is :

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\frac{2 cos 67 ^{o}}{sin 23 ^{o}} + \frac{tan 40 ^{o}}{cot 50 ^{o}} - sin 90^{o}

= \frac{2 cos 67 ^{o}}{cos ( 90 ^{o} - 23 ^{o} )} - \frac{tan 40 ^{o}}{tan ( 90 ^{o} - 50 ^{o} )} - sin 90^{o}

= \frac{2 cos 67 ^{o}}{cos 67 ^{o}} - \frac{tan 40 ^{o}}{tan 40 ^{o}} - sin 90^{o}

= 2 - 1 - 1 = 0

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Question Text	The value of $\frac{2 cos 67 ^{o}}{sin 23 ^{o}} - \frac{tan 40 ^{o}}{cot 50 ^{o}} - sin 90^{o}$ is :
Answer Type	Text solution:1
Upvotes	150