The value of $(4 t a n^{2} A - 4 se c^{2} A)$ is equal to :

- 1

- 4

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The value of

(4 t a n^{2} A - 4 se c^{2} A)

is equal to :

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Text solutionVerified

4 tan^{2} A - 4 sec^{2} A = 4 tan^{2} A - 4 (1 - tan^{2} A)

= 4 tan^{2} A - 4 - 4 tan^{2} A

= - 4

Hence, the answer is

- 4.

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Question Text	The value of $(4 t a n^{2} A - 4 se c^{2} A)$ is equal to :
Answer Type	Text solution:1
Upvotes	153