The sum of two numbers is 8 and the of squares is 34. The product of the two numbers is

(c): Let the two numbers are x and y. x+y=8 and        x2+y2=34 Now, we have (x+y)2=(x2+y2)+2xy ⇒(x+y)2−(x2+y2)=2xy      ⇒xy=12[(x+y)2−(x2+y2)] =12[(8)2−(34)] =12[64−34]=12×30=15