The solution of the D.E. dxdy=1−x+y−xy is

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The solution of the D.E. {dy}{dx}=1-x+y-xy is

Question

The solution of the D.E. $\frac{d y}{d x} = 1 - x + y - x y$ is

lo g (1 + y) = x - \frac{x ^{2}}{2} + C

e^{(1 + y)} = x - \frac{x ^{2}}{2} + C

e^{y} = x - \frac{x ^{2}}{2} + C

n o n e o f t h ese

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The solution of the D.E.

\frac{d y}{d x} = 1 - x + y - x y

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Question Text

The solution of the D.E.

\frac{d y}{d x} = 1 - x + y - x y