The base of a right-angled triangle measures 48 cm and its hypotenuse measures 50 cm. Find the area of the triangle.

We are given with a right-angled triangle whose measures are
Base $=48cm$
Hypotenuse $=50cm$

Using Pythagoras Theorem:
Hypotenuse${}^2=$ Base${}^2+$ Perpendicular${}^2$
$50^2=48^2+$ Perpendicular${}^2$
or Perpendicular ${}^2=2500-2304=196$
or Perpendicular $=14cm$

Now,
Area of a triangle $=\frac{1}{2}\times Base\times Height$
                              $=\frac{1}{2}\times 48cm\times 14cm$
                              $=336c{m}^2$