cosec (75∘+θ)−sec(15∘−θ)=

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{cosec } (75^{} + ) - (15^{} - ) =

Question

$cosec (7 5^{\circ} + θ) - sec (1 5^{\circ} - θ) =$

2 sec θ

2 cosec θ

0

1

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Sebastian Discussed

cosec (7 5^{\circ} + θ) - sec (1 5^{\circ} - θ) =

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14 mins ago

Given,

csc (7 5^{o} + θ) - sec (1 5^{o} - θ)

= csc (7 5^{o} + θ) - sec [9 0^{o} - (7 5^{o} + θ)]

= csc (7 5^{o} + θ) - csc (7 5^{o} + θ)

= 0

0

will be the answer

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