tan9o×tan27o×tan63o×tan81o=

tan9∘ .tan27∘ .tan63∘ .tan81∘ =tan(90∘ −81∘ ).tan(90∘ −63∘ ).tan63∘ .tan81∘ =cot81∘ .cot63∘ .tan63∘ .tan81∘ =1

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9^o 27^o 63^o 81^o=

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$tan 9^{o} \times tan 2 7^{o} \times tan 6 3^{o} \times tan 8 1^{o} =$

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tan 9^{o} \times tan 2 7^{o} \times tan 6 3^{o} \times tan 8 1^{o} =

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tan 9^{\circ} . tan 27^{\circ} . tan 63^{\circ} . tan 81^{\circ} = tan (90^{\circ} - 81^{\circ}) . tan (90^{\circ} - 63^{\circ}) . tan 63^{\circ} . tan 81^{\circ} = cot 81^{\circ} . cot 63^{\circ} . tan 63^{\circ} . tan 81^{\circ} = 1

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Question Text	$tan 9^{o} \times tan 2 7^{o} \times tan 6 3^{o} \times tan 8 1^{o} =$
Answer Type	Text solution:1
Upvotes	150