sin84∘+sec84∘ expressed in terms of angles between 0∘ and 45∘ becomes

We know thatsinA=cos(90˚−A)tanA=cot(90˚−A)secA=cosec (90˚−A)Using these, we getsin84∘=cos(90˚−84˚)=cos6∘sec84∘=cosec (90˚−84˚)=cosec 6∘∴sin84∘+sec84∘=cos6∘+cosec 6∘.

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84^{} + 84^{} expressed in terms of angles between 0^{} and

Question

$sin 8 4^{\circ} + sec 8 4^{\circ}$ expressed in terms of angles between $0^{\circ}$ and $4 5^{\circ}$ becomes

cos 6^{\circ} + cosec 6^{\circ}

sin 6^{\circ} + cos 6^{\circ}

sin 6^{\circ} + cosec 6^{\circ}

None of these

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sin 8 4^{\circ} + sec 8 4^{\circ}

expressed in terms of angles between

0^{\circ}

and

4 5^{\circ}

becomes

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

We know that

sin A = cos (90˚ - A)

tan A = cot (90˚ - A)

sec A = cosec (90˚ - A)

Using these, we get

sin 8 4^{\circ} = cos (90˚ - 84˚) = cos 6^{\circ}

sec 8 4^{\circ} = cosec (90˚ - 84˚) = cosec 6^{\circ}

∴ sin 8 4^{\circ} + sec 8 4^{\circ} = cos 6^{\circ} + cosec 6^{\circ}

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Question Text	$sin 8 4^{\circ} + sec 8 4^{\circ}$ expressed in terms of angles between $0^{\circ}$ and $4 5^{\circ}$ becomes
Answer Type	Text solution:1
Upvotes	150

sin84∘+sec84∘ expressed in terms of angles between 0∘ and 45∘ becomes

Text solutionVerified

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$sin 8 4^{\circ} + sec 8 4^{\circ}$ expressed in terms of angles between $0^{\circ}$ and $4 5^{\circ}$ becomes