sin30o =21 cos60o =21sin30o −cos60o =21−21=0

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30^{o}- cos60^{o}= ?

Question

$sin 3 0^{o} - cos 6 0^{o}$ = ?

0

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\frac{1}{2}

2

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sin 3 0^{o} - cos 6 0^{o}

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Text solutionVerified

sin 30^{o} = \frac{1}{2}

cos 60^{o} = \frac{1}{2}

sin 30^{o} - cos 60^{o} = \frac{1}{2} - \frac{1}{2} = 0

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