Class 10 Math All topics Quadratic Equations

One year ago a man was eight times old as his son . Now his age is equal to the square of his son's age . Represent this situation in form of a quadratic equation

Solution: Let the present age of man be $x_{2}$

His son age is $x$

One year ago, his age is $x_{2}−1$

His son age is $x−1$

According to question

$x_{2}−1=8(x−1)x_{2}−8x+7=0$

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introduction to trigonometry

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introduction to trigonometry

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quadratic equations

surface areas and volumes

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