On a square handkerchief, nine circular designs each of radius7 cm are made (see the given figure). Find the area of the remaining portion of the handkerchief. [Useπ=722]

Question

On a square handkerchief, nine circular designs each of radius7 cm are made (see the given figure). Find the area of the remaining portion of the handkerchief. [Useπ=722​]

Filo · Accepted Answer

Area of the remaining portion = Area of square − Area of 9 circles.Here, the handkerchief is made up of contributing 9 circles.So, side of the square =3× Diameter of circleHere, the radius of a circle is 7cm∴ Diameter of circle is 14cm⇒side of a square =3×14=42cm∴ Area of the square =42×42=1764cm2Area of one circle is πr2=722​×72=154cm2Hence area of 9 circles is 9×154=1386cm2∴ Area of the remaining portion = Area of square − Area of 9 circles.                                                      =1764−1386                                                      =378cm2Hence, area of the remaining portion is 378cm2

Question Text	On a square handkerchief, nine circular designs each of radius $7$ cm are made (see the given figure). Find the area of the remaining portion of the handkerchief. $[Use π = \frac{22}{7}]$
Answer Type	Text solution:1
Upvotes	150

On a square handkerchief, nine circular designs each of radius $7$ cm are made (see the given figure). Find the area of the remaining portion of the handkerchief. $[Use π = \frac{22}{7}]$

Text solutionVerified

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On a square handkerchief, nine circular designs each of radius7 cm are made (see the given figure). Find the area of the remaining portion of the handkerchief. [Useπ=722​]

Text solutionVerified

Practice questions from similar books

On a square handkerchief, nine circular designs each of radius $7$ cm are made (see the given figure). Find the area of the remaining portion of the handkerchief. $[Use π = \frac{22}{7}]$