Let fK(x)=k1(s∈kx+coskx)where x∈Rand k≥1. Then f4(x)−f6(x)equals

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Question

Let $f_{K} (x) = \frac{1}{k} (s \in^{k} x + cos^{k} x)$ where $x \in R$ and $k \geq 1$ . Then $f_{4} (x) - f_{6} (x)$ equals

\frac{1}{6}

\frac{1}{3}

\frac{1}{4}

\frac{1}{12}

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Elizabeth Discussed

Let

f_{K} (x) = \frac{1}{k} (s \in^{k} x + cos^{k} x)

where

x \in R

and

k \geq 1

. Then

f_{4} (x) - f_{6} (x)

equals

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Question Text	Let $f_{K} (x) = \frac{1}{k} (s \in^{k} x + cos^{k} x)$ where $x \in R$ and $k \geq 1$ . Then $f_{4} (x) - f_{6} (x)$ equals
Answer Type	Video solution: 1
Upvotes	150