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In what ratio does the point C(4, 5) divide the join of A(2, 3

Question

In what ratio does the point $C (4, 5)$ divide the join of $A (2, 3)$ and $B (7, 8)$ ?

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In what ratio does the point

C (4, 5)

divide the join of

A (2, 3)

and

B (7, 8)

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

Using the section formula, if a point

(x, y)

divides the line joining the points

(x_{1}, y_{1})

and

(x_{2}, y_{2})

in the ratio

m : n

, then

(x, y) = (\frac{m x _{2} + n x _{1}}{m + n}, \frac{m y _{2} + n y _{1}}{m + n})

Point

C (4, 5)

divide the join of

A (2, 3)

and

B (7, 8)

Let point

C (4, 5)

divides the AB in the ratio

m : n

Using section formula:

x = \frac{m x _{2} + n x _{1}}{m + n}

4 = \frac{m ( 7 ) + n ( 2 )}{m + n}

4 m + 4 n = 7 m + 2 n

3 m = 2 n

m : n = 2 : 3

The requried ratio is

2 : 3

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Question Text	In what ratio does the point $C (4, 5)$ divide the join of $A (2, 3)$ and $B (7, 8)$ ?
Answer Type	Text solution:1
Upvotes	150