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In the adjoining figure, DE||BC. Prove that ar( ACD)=ar ( ABE)

Question

In the adjoining figure, $D E ∣∣ BC$ . Prove that
$a r (△ A C D) = a r (△ A BE)$

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In the adjoining figure,

D E ∣∣ BC

. Prove that

a r (△ A C D) = a r (△ A BE)

15 mins ago

Discuss this question LIVE

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Text solutionVerified

We know that

△ D BE

= Area of

△ D CE

.....(Triangles with same base and equal sides )

By adding

△ A D E

both sides

Area of

△ A BE =

Area of

△ A C D

Therefore, it is proved that

a r (△ A C D) = a r (△ A BE)

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Question Text	In the adjoining figure, $D E ∣∣ BC$ . Prove that $a r (△ A C D) = a r (△ A BE)$
Answer Type	Text solution:1
Upvotes	150