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In an AP: given a = 3, n = 8, S = 192, find 'd'.

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In an AP:
given $a = 3, n = 8, S = 192,$ find 'd'.

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In an AP:
given

a = 3, n = 8, S = 192,

find 'd'.

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Text solutionVerified

S_{n} = \frac{n}{2} [2 a + (n - 1) d]

S_{8} = \frac{8}{2} [2 \times 3 + (8 - 1) d] = 192

\frac{8}{2} [6 + 7 \times d] = 192

4 (6 + 7 d) = 192

6 + 7 d = 48

7 d = 48 - 6

7 d = 42

d = \frac{42}{7}

∴ d = 6

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