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If x=3+i then prove that x^2-6x+13=0.

Question

If $x = 3 + i$ then prove that $x^{2} - 6 x + 13 = 0$ .

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Evelyn Discussed

x = 3 + i

then prove that

x^{2} - 6 x + 13 = 0

7 mins ago

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7 mins ago

Text solutionVerified

Given,

x = 3 + 2 i

or,

x - 3 = 2 i

Now squaring both sides we get,

(x - 3)^{2} = - 4

or,

x^{2} - 6 x + 9 = - 4

or,

x^{2} - 6 x + 13 = 0

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