If θ=30o, then cos2θ1−sin22θ is

cos2θ1−sin22θ=cos2×30o1−sin22×30o=cos60o1−sin260o=211−(23)2211−43=2144−3→41×12=21

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If =30^o, then {1-^22}{ 2} is

Question

If $θ = 3 0^{o}$ , then $\frac{1 - sin ^{2} 2 θ}{cos 2 θ}$ is

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Theodore Discussed

θ = 3 0^{o}

, then

\frac{1 - sin ^{2} 2 θ}{cos 2 θ}

7 mins ago

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7 mins ago

\frac{1 - s i n ^{2} 2 θ}{cos 2 θ} = \frac{1 - sin ^{2} 2 \times 3 0 ^{o}}{cos 2 \times 3 0 ^{o}}

= \frac{1 - sin ^{2} 6 0 ^{o}}{cos 6 0 ^{o}} = \frac{1 - ( \frac{3}{2} ) ^{2}}{\frac{1}{2}}

\frac{1 - \frac{3}{4}}{\frac{1}{2}} = \frac{\frac{4 - 3}{4}}{\frac{1}{2}} \to \frac{1}{4} \times \frac{2}{1} = \frac{1}{2}

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