If tan2A=cot(A−21∘), where 2A is an acute angle, then ∠A= ____

Given, tan2A=cot(A−21∘)Therefore, cot(90−2A)=cot(A−21∘)⇒90−2A=A−21∘ ⇒90∘+21∘=2A+A⇒ 111=3A⇒A=37∘So, ∠A=37∘ is correct.

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If 2A = (A - 21^{}), where 2A is an acute angle, then A = _

Question

If $tan 2 A = cot (A - 2 1^{\circ})$ , where $2 A$ is an acute angle, then $∠ A =$ ____

2 4^{\circ}

2 7^{\circ}

3 5^{\circ}

3 7^{\circ}

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Eleanor Discussed

tan 2 A = cot (A - 2 1^{\circ})

, where

2 A

is an acute angle, then

∠ A =

____

12 mins ago

Discuss this question LIVE

12 mins ago

Given,

tan 2 A = cot (A - 2 1^{\circ})

Therefore,

cot (90 - 2 A) = cot (A - 2 1^{\circ})

\Rightarrow 90 - 2 A = A - 2 1^{\circ}

\Rightarrow 9 0^{\circ} + 2 1^{\circ} = 2 A + A

\Rightarrow 111 = 3 A

\Rightarrow A = 3 7^{\circ}

So,

∠ A = 3 7^{\circ}

is correct.

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Question Text	If $tan 2 A = cot (A - 2 1^{\circ})$ , where $2 A$ is an acute angle, then $∠ A =$ ____
Answer Type	Text solution:1
Upvotes	150