If sinθ=1312, where θ is an acute angle, find the value of cosθ

Given: sinθ=1312To find: cosθWe know that,sinθ=HP=ACAB=1312According to Pythagoras theorem,P2+B2=H2(12)2+B2=(13)2B2=169−144B2=25B=5=BCcosθ=HB=135cosθ=135

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If = {12}{13}, where is an acute angle, find the value of

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If $sin θ = \frac{12}{13}$ , where $θ$ is an acute angle, find the value of $cos θ$

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sin θ = \frac{12}{13}

, where

θ

is an acute angle, find the value of

cos θ

11 mins ago

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Text solutionVerified

Given:

sin θ = \frac{12}{13}

To find:

cos θ

We know that,

sin θ = \frac{P}{H} = \frac{A B}{A C} = \frac{12}{13}

According to Pythagoras theorem,

P^{2} + B^{2} = H^{2}

(12)^{2} + B^{2} = (13)^{2}

B^{2} = 169 - 144

B^{2} = 25

B = 5 = BC

cos θ = \frac{B}{H} = \frac{5}{13}

cos θ = \frac{5}{13}

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Question Text	If $sin θ = \frac{12}{13}$ , where $θ$ is an acute angle, find the value of $cos θ$
Answer Type	Text solution:1
Upvotes	150

If sinθ=1312​, where θ is an acute angle, find the value of cosθ

Text solutionVerified

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If $sin θ = \frac{12}{13}$ , where $θ$ is an acute angle, find the value of $cos θ$