If sin θ=51, then the value of 51cot2θ+51 is equal to :

sinθ =51⇒51cot2θ +51=51[cot2θ +1]=5cosec2θ =5sec2θ 1=5×251 1=51 1=5Hence, the answer is 5.

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If sin ={1}{5}, then the value of {1}{5} cot^{2} +{1}{5} is

Question

If sin $θ = \frac{1}{5}$ , then the value of $\frac{1}{5} co t^{2} θ + \frac{1}{5}$ is equal to :

\frac{1}{125}

\frac{1}{5}

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Michael Discussed

If sin

θ = \frac{1}{5}

, then the value of

\frac{1}{5} co t^{2} θ + \frac{1}{5}

is equal to :

5 mins ago

Discuss this question LIVE

5 mins ago

sin θ = \frac{1}{5}

\Rightarrow \frac{1}{5} cot^{2} θ + \frac{1}{5} = \frac{1}{5} [cot^{2} θ + 1]

= \frac{cose c ^{2} θ}{5}

= \frac{1}{5 sec ^{2} θ}

= \frac{1}{5 \times \frac{1}{25}}

= \frac{1}{\frac{1}{5}}

= 5

Hence, the answer is

5.

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Question Text	If sin $θ = \frac{1}{5}$ , then the value of $\frac{1}{5} co t^{2} θ + \frac{1}{5}$ is equal to :
Answer Type	Text solution:1
Upvotes	150