If one zero of the polynomial $x^2-4x+1$ is $(2+\sqrt{3})$ write the other zero.

Given : $(2+\sqrt{3})$ is one of the polynomial $x^2-4x+1$
to find : other zero

since given polynomial is quadratic so it has only two zeros.

Let other zero be $x.$
Now, Sum of zero = \dfrac {-( coefficient \  of \  x)}{(coefficient \  of \   x^2 )}

$x+(2+\sqrt{3})=-\frac{(-4)}{}1=4$

$x+2+\sqrt{3}=4$

or \  x = 2 - \sqrt {3}

hence , the other zero is $(2-\sqrt{3})$