If tan2A=cot (A−60∘), where 2A is an acute angle, then the value of A is

tan2A=cot (A−60∘)cot(90−2A)=cot(A−60)90−2A=A−603A=150A=50∘

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If 2A= (A-60^{}), where 2A is an acute angle, then the valu

Question

If $tan 2 A = cot (A - 6 0^{\circ}),$ where 2A is an acute angle, then the value of A is

3 0^{\circ}

6 0^{\circ}

5 0^{\circ}

2 4^{\circ}

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tan 2 A = cot (A - 6 0^{\circ}),

where 2A is an acute angle, then the value of A is

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10 mins ago

tan 2 A = cot (A - 6 0^{\circ})

cot (90 - 2 A) = cot (A - 60)

90 - 2 A = A - 60

3 A = 150

A = 5 0^{\circ}

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Question Text	If $tan 2 A = cot (A - 6 0^{\circ}),$ where 2A is an acute angle, then the value of A is
Answer Type	Text solution:1
Upvotes	150