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If ( x+ x ) ( y+ y ) ( z+ z )= ( x- x ) ( y- z )=K

Question

If $(tan x + sec x) (tan y + sec y) (tan z + sec z) = (sec x - tan x) (sec y - tan z) = K$ , then the value of $K$ is

\pm 2

\pm 3

\pm 2

\pm 1

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(tan x + sec x) (tan y + sec y) (tan z + sec z) = (sec x - tan x) (sec y - tan z) = K

, then the value of

K

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Text solutionVerified

(tan x + sec x)^{2} (tan y + sec y)^{2} (tan z + sec z)^{2}

= (sec^{2} x - tan^{2} x) (sec^{2} y - tan^{2} y) (sec^{2} z - tan^{2} z)

= 1 \times 1 \times 1 = 1 = k^{2}

∴ K = \pm 1

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Question Text	If $(tan x + sec x) (tan y + sec y) (tan z + sec z) = (sec x - tan x) (sec y - tan z) = K$ , then the value of $K$ is
Answer Type	Text solution:1
Upvotes	151