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From the figure (i) given below, calculate all the six t-ratio

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From the figure (i) given below, calculate all the six t-ratios for angle A

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Text solutionVerified

From right angled triangle ABC,
By Pythagoras theorem, we get

A C^{2} = A B^{2} + B C^{2}

A B^{2} = A C^{2} - B C^{2}

A B^{2} = (3)^{2} - (2)^{2}

A B^{2} = 9 - 4

A B^{2} = 5

A B = \sqrt 5

(i) sin A = perpendicular/ hypotenuse
= BC/AC

= 2/3

(ii) cos A = base/ hypotenuse
= AB/AC
=

\sqrt 5 /3

(iii) tan A = perpendicular/ base
= BC/AB

= 2/\sqrt 5

(iv) cot A = base/perpendicular
= AB/ BC

= \sqrt 5 /2

(v) sec A = hypotenuse/ base
= AC/AB

= 3/\sqrt 5

(vi) cosec A = hypotenuse/perpendicular
= AC/BC

= 3/2

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Question Text	From the figure (i) given below, calculate all the six t-ratios for angle A
Answer Type	Text solution:1
Upvotes	150