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For p=99 then find the value of p^3+3p^2+3p

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For $p = 99$ then find the value of $p^{3} + 3 p^{2} + 3 p$

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For

p = 99

then find the value of

p^{3} + 3 p^{2} + 3 p

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Text solutionVerified

We have,

$p = 99$

Since,

$\Rightarrow p^{3} + 3 p^{2} + 3 p + 1 - 1$

$\Rightarrow (p + 1)^{3} - 1$

$\Rightarrow (99 + 1)^{3} - 1$

$\Rightarrow (100)^{3} - 1$

$\Rightarrow 1000000 - 1$

$\Rightarrow 999999$

Hence, this is the answer.

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Question Text	For $p = 99$ then find the value of $p^{3} + 3 p^{2} + 3 p$
Answer Type	Text solution:1
Upvotes	150