Class 10 Math All topics Quadratic Equations

For $p=99$ then find the value of $p_{3}+3p_{2}+3p$

Solution:

We have,

$p=99$

Since,

$⇒p_{3}+3p_{2}+3p+1−1$

$⇒(p+1)_{3}−1$

$⇒(99+1)_{3}−1$

$⇒(100)_{3}−1$

$⇒1000000−1$

$⇒999999$

Hence, this is the answer.

Similar topics

introduction to trigonometry

functions

some applications of trigonometry

quadratic equations

polynomials

introduction to trigonometry

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quadratic equations

polynomials

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