Find the value of sec2θ1+cosec2θ1

sec2θ1+cosec2θ1=cos2θ+sin2θ=1

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Find the value of {1}{^2 } + {1}{cosec^2 }

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Find the value of
$\frac{1}{sec ^{2} θ} + \frac{1}{cose c ^{2} θ}$

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Find the value of

\frac{1}{sec ^{2} θ} + \frac{1}{cose c ^{2} θ}

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\frac{1}{sec ^{2} θ} + \frac{1}{cose c ^{2} θ} = cos^{2} θ + sin^{2} θ = 1

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Question Text	Find the value of $\frac{1}{sec ^{2} θ} + \frac{1}{cose c ^{2} θ}$
Answer Type	Text solution:1
Upvotes	150