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Find the sum of the first 40 positive integers divisible by 6.

Question

Find the sum of the first $40$ positive integers divisible by $6$ .

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Find the sum of the first

40

positive integers divisible by

6

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

The first

40

positive integers that are divisible by

6

are

6, 12, 18, 24 \dots

a = 6

and

d = 6

We need to find

S_{40}

S_{n} = \frac{n}{2} [2 a + (n - 1) d]

S_{40} = \frac{40}{2} [2 (6) + (40 - 1) 6]

= 20 [12 + (39) 6]

= 20 (12 + 234)

= 20 \times 246

= 4920

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Question Text	Find the sum of the first $40$ positive integers divisible by $6$ .
Answer Type	Text solution:1
Upvotes	150