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Find the sum of the first 15 multiples of 8.

Question

Find the sum of the first $15$ multiples of $8$ .

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Find the sum of the first

15

multiples of

8

12 mins ago

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12 mins ago

Text solutionVerified

The multiples of

8

are

8, 16, 24, 32 \dots

These are in an A.P., having first term as

8

and common difference as

8

.
Therefore,

a = 8, d = 8

S_{15} = ?

S_{n} = \frac{n}{2} [2 a + (n - 1) d]

S_{15} = \frac{15}{2} [2 (8) + (15 - 1) 8]

= \frac{15}{2} [16 + (14) (8)]

= \frac{15 \times 128}{2}

= 960

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Question Text	Find the sum of the first $15$ multiples of $8$ .
Answer Type	Text solution:1
Upvotes	150