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Find the area of the triangle whose vertices are (i) {({2},{3}

Question

Find the area of the triangle whose vertices are
(i) $(2, 3), (- 1, 0), (2, - 4)$
(ii) $(- 5, - 1), (3, - 5), (5, 2)$

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Find the area of the triangle whose vertices are
(i)

(2, 3), (- 1, 0), (2, - 4)

(ii)

(- 5, - 1), (3, - 5), (5, 2)

13 mins ago

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Text solutionVerified

Solution: Area of a triangle,

A =

\frac{1}{2} (x_{1} (y_{2} - y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (y_{1} - y_{2}))

(i)

A = \frac{1}{2} (2 (0 - (- 4) + (- 1) (- 4 - 3) + 2 (3 - 0)) = \frac{1}{2} (8 + 7 + 6)

= \frac{21}{2}

square units
(ii)

A = \frac{1}{2} ((- 5) (- 5 - 2) + 3 (2 - (- 1)) + 5 (- 1 - (- 5)) = \frac{1}{2} (35 + 9 + 20)

= 32

square units.

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Question Text	Find the area of the triangle whose vertices are (i) $(2, 3), (- 1, 0), (2, - 4)$ (ii) $(- 5, - 1), (3, - 5), (5, 2)$
Answer Type	Text solution:1
Upvotes	150