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Find the area of rhombus if its vertices are (3, 0), (4, 5), (

Question

Find the area of rhombus if its vertices are $(3, 0), (4, 5), (- 1, 4)$ and $(- 2, - 1)$ taken in order.
[Hint: Area of rhombus $= \frac{1}{2} \times$ product of its diagonals.]

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Find the area of rhombus if its vertices are

(3, 0), (4, 5), (- 1, 4)

and

(- 2, - 1)

taken in order.

[Hint: Area of rhombus

= \frac{1}{2} \times

product of its diagonals.]

13 mins ago

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Text solutionVerified

We know that,

Area of Rhombus

= \frac{1}{2}

(Product of its diagonals)

Given co-ordinates of rhombus are

(3, 0), (4, 5), (- 1, 4)

and

(- 2, - 1)

Diagonal

1 = (3 + 1)^{2} + (0 - 4)^{2} = 42

Diagonal

2 = (4 + 2)^{2} + (5 + 1)^{2} = 62

∴

Area of rhombus

= \frac{1}{2} (42 \times 62)

= 24

unit

^{2}

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Question Text	Find the area of rhombus if its vertices are $(3, 0), (4, 5), (- 1, 4)$ and $(- 2, - 1)$ taken in order. [Hint: Area of rhombus $= \frac{1}{2} \times$ product of its diagonals.]
Answer Type	Text solution:1
Upvotes	150