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Find the area of ABC whose vertices are A(3, 8), B(-4, 2) and

Question

Find the area of $Δ A BC$ whose vertices are $A (3, 8), B (- 4, 2)$ and $C (5, - 1)$ .

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Find the area of

Δ A BC

whose vertices are

A (3, 8), B (- 4, 2)

and

C (5, - 1)

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

Area of

Δ A BC

whose vertices are is

(x_{1}, y_{1}), (x_{2}, y_{2})

and

(x_{3}, y_{3})

are

Area of

Δ A BC = \frac{1}{2} [x_{1} (y_{2} - y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (y_{1} - y_{2})]

Δ A BC

, vertices are

A (3, 8), B (- 4, 2)

and

C (5, - 1)

Area of triangle

= \frac{1}{2} (3 (2 + 1) - 4 (- 1 - 8) + 5 (8 - 2))

= \frac{1}{2} (9 + 36 + 30)

= \frac{1}{2} (75)

= 37.5

sq units.

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Question Text	Find the area of $Δ A BC$ whose vertices are $A (3, 8), B (- 4, 2)$ and $C (5, - 1)$ .
Answer Type	Text solution:1
Upvotes	150